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18t^2-72=0
a = 18; b = 0; c = -72;
Δ = b2-4ac
Δ = 02-4·18·(-72)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*18}=\frac{-72}{36} =-2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*18}=\frac{72}{36} =2 $
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